Kl Rahul becomes fastest Indian to complete 2,000 runs in IPL, Gayle achieves fastest in 48 innings.
Kings XI Punjab has given a target of 207 to Royal Challengers Bangalore in Dubai through a superb inning by captain Lokesh Rahul. Punjab have scored 206 runs for the loss of 3 wickets in 20 overs. For him, Rahul scored 132 * off 69 balls with the help of 14 fours and 7 sixes. This is the second century in his league. He also became the fastest Indian to complete 2,000 runs in the league.
Rahul got a lifeline twice, Kohli dropped the catch while batting 83 and 89.
Mayank Agarwal was bowled by Yuzvendra Chahal. He scored 26 off 20 balls with the help of 4 fours. He shared a 57-run stand with Rahul for the first wicket. Nicholas Pooran was then caught out by De Villiers at mid-off off Shivam Dubey for 17. Glenn Maxwell was caught out by Finch on Dubey's bowling covers. He scored 5 off 6 balls.
Fastest 2000 thousand in IPL:
- 48 innings: Chris Gayle
- 52 Innings: Shaun Marsh
- 60 innings: Lokesh Rahul
Royal Challengers Bangalore won the toss and elected to bowl first
Royal Challengers Bangalore skipper Virat Kohli has decided to bowl after winning the toss against Kings XI Punjab at the Dubai International Cricket Stadium. Bangalore are unbeaten against Punjab in the last 4 matches. He made no changes to his playing 11. While Chris Jordan and K. in the Punjab team. Gautam has been replaced by Murugan Ashwin and Jimmy Neesham.
KL Rahul now has the highest score ever by an Indian in IPL.#Dream11IPL #KXIPvRCB pic.twitter.com/zu8r2kTeWW
— IndianPremierLeague (@IPL) September 24, 2020
He's brilliant, isn't he! KL Rahul powers Kings XI Punjab to 206/3 - those two Kohli drops may just prove very costly for RCBhttps://t.co/bOVIx1062N #KXIPvRCB #IPL2020 pic.twitter.com/fuzRSCMBJ5
— ESPNcricinfo (@ESPNcricinfo) September 24, 2020
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